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3 years ago

what are the first 5 common multiples of 14 and 20? i’ll mark brainliest for whoever answers first!!!

Mathematics

2 answers:

shutvik [7]3 years ago

8 0

Answer:

14, 28, 42, 56, and 70 are the first 5 common multiples of 14

20, 40, 60, 80, and 100 are the first 4 common multiples of 20

Serga [27]3 years ago

6 0

Answer: 14 : 14,28,42,56,70

20: 20,40,60,60,100

lcm is 140

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Andreas93 [3]

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3 years ago

Solve the compound inequality. |x-3| 8.

DanielleElmas [232]

8x-24
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5 0

3 years ago

Find the value of x and show work

Oksana_A [137]

Step-by-step explanation:

35+35+x=180 (sum of interior angles of an triangle is 180

therefore

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3 0

3 years ago

Which of the following are operations in the algebra of sets?

postnew [5]

Answer:

Union and Intersection

Step-by-step explanation:

We know that the algebra of sets define the properties and laws of the sets.

The basic operations of sets are,

Union, Intersection, Complement of a set and Equality of sets.

Since, the operations addition, subtraction, multiplication and division are the basic arithmetic operations of numbers.

i.e. they are not in the algebra of sets.

So, we get that out of the given options, the operations in algebra of sets are Union and Intersection.

7 0

3 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 8.2\text{ cm}8.2 cm and the height of the py

7nadin3 [17]

Answer:

$V=18.2cm^3$

Step-by-step explanation:

The volume of the pyramid is given by:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height.

We know that the height is:

$h=13cm$

Thus we need to find the area of the square at the base.

The perimeter of the square is:

$p=8.2cm$

this means that the length of the sides of the square is :

$l=\frac{p}{4}\\ \\l=\frac{8.2cm}{4}\\ \\l=2.05cm$

Now we can find the area of the base which the area of the square:

$A_{b}=l^2\\A_b=(2.05cm)^2\\A_b=4.2025cm^2$

and finally we find the volume:

$V=\frac{A_{b}h}{3}$

$V=\frac{(4.2025cm^2)(13cm)}{3}\\ \\V=\frac{54.6325cm^3}{3}\\ \\V=18.2108cm^3$

Which rounded to the nearest tenth of a cubic centimeter is: $V=18.2cm^3$

3 0

3 years ago