In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
are diameters of circle PPP. What is the arc measure of \stackrel{\LARGE{\frown}}{CD} CD ⌢ C, D, start superscript, \frown, end superscript in degrees? ^\circ ∘ degrees
1 answer:
Answer:
<u>The measure of the arc CD = 64°</u>
Step-by-step explanation:
The rest of the question is the attched figure.
It is required to find the measure of the arc CD in degrees.
as shown at the graph
BE and AD are are diameters of circle P
And ∠APE is a right angle ⇒ ∠APE = 90°
So, BE⊥AD
And so, ∠BPE = 90° ⇒(1)
But it is given: ∠BPE = (33k-9)° ⇒(2)
From (1) and (2)
∴ 33k - 9 = 90
∴ 33k = 90 + 9 = 99
∴ k = 99/33 = 3
The measure of the arc CD = ∠CPD = 20k + 4
By substitution with k
<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>
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radius of bottle is 7 cm. height is 28 cm
so total milk in bottle is equal to total volum of bottle.
so volume of cylinder is = pi × r^2 × h
V = (22/7 )× 7×7×28 = 22×7×28
= 4312 cm^3
so volume of the milk before used to make tea is 4312 cm^3
now milk taken to make tea make height reduced to 20 cm.
so volume of the left milk in bottole is
= (22/7) × 7×7×20 = 22×7×20
= 3080 cm^3
so milk used for making tea = total milk before making the tea - total milk left in bottle after making the tea
= 4312 - 3080 = 1232 cm ^3
so volume of milk used
