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3 years ago

A field having length 120ft and width 90ft has a squared pond with edge 20ft . find the area of the field excluding the pond.

Mathematics

1 answer:

xeze [42]3 years ago

7 0

Isnt it 10,800 ft I could be very wrong

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Find the distance between (8, -4.7) and (8, 5.3)

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Answer:

d = 10

Step-by-step explanation:

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4 years ago

Miranda says that 30x26 is greater than 20x36 is she correct ?

julsineya [31]

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3 years ago

Read 2 more answers

PROVE THAT:<br><br>cos 20° - sin 20° = \sqrt{2}sin25°<br><br>

Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

$\cos(20)-\sin(20)=\sqrt{2}\sin(25)$

First, use the co-function identity:

$\sin(90-x)=\cos(x)$

We can turn the second term into cosine:

$\sin(20)=\sin(90-70)=\cos(70)$

Substitute:

$\cos(20)-\cos(70)=\sqrt{2}\sin(25)$

Now, use the sum to product formulas. We will use the following:

$\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})$

Substitute:

$\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70) =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)$

Use the even-odd identity:

$\sin(-x)=-\sin(x)$

Therefore:

$\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)$

Replace the second term with the original term:

$\cos(20)-\sin(20)=\sqrt{2}\sin(25)$

Proof complete.

4 0

4 years ago

Find the perimeter of the figure. Please

kramer

The dashed line labeled as 6 is the diameter of the circular part of the figure.

The circumference of a circle is it's perimeter, so we need to find half the circumference first.

The formula for circumference is PI x diameter, since we need half we will divide the total circumference by 2.

Circumference = 3.14 x 6 = 18.85 / 2 = 9.425

Now we add that to the other 3 dimensions for total perimeter:

9.425 + 9 + 9 +6 = 33.425

You may need to round the answer, you didn't say if it needed to be rounded a certain way.

5 0

4 years ago

A field having length 120ft and width 90ft has a squared pond with edge 20ft . find the area of the field excluding the pond.​

A field having length 120ft and width 90ft has a squared pond with edge 20ft . find the area of the field excluding the pond.