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shtirl [24]
3 years ago
13

Find the distance between (8, -4.7) and (8, 5.3)

Mathematics
1 answer:
irina [24]3 years ago
8 0

Answer:

d = 10

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(8-8)^2+(5.3-(-4.7))^2} \\d= \sqrt{(0)^2+(10)^2} \\d= \sqrt{0+100} \\d= \sqrt{100}\\ d= 10

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If 1/2 +2/5s =s-3/4, what is the value of s?
jeyben [28]

Answer:

s= 25/12 or 2.0833333

Step-by-step explanation:

explanation in pictures

8 0
3 years ago
Read 2 more answers
2,5,15,18,54,57.....<br> পরের সংখ্যা কত
Tomtit [17]

Answer:

171 (assuming that you want to know the next term)

Step-by-step explanation:

We get from 2 to 5 by adding 3. We then get from 5 to 15 by multiplying by 3.

This pattern repeats so to get from 54 to 57 we have added 3 again so to get the next term we multiply 57 by 3 to give 171.

6 0
3 years ago
5. List the Amplitude, Horizontal DilatioGraph the parent
dalvyx [7]

2n n2 3n 2x 2n 3n x 3 x 2x 3n 3x

7 0
3 years ago
4/? = ?/ 9
svet-max [94.6K]

Set ? as x, and cross-multiply.

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3 0
4 years ago
Suppose that the distribution is bell-shaped. If approximately 99.7% of the lifetimes lie between 568 hours and 1066 hours, then
irakobra [83]

Answer:

\sigma =\frac{478}{6}=79.667

Step-by-step explanation:

The empirical rule, also referred to as "the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)". The empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

And on this case since we are within 3 deviations (because we have 99.7% of the data between 568 and 1066hours), the result obtained using the z score agrees with the empirical rule.  

So on this case we can find the standard deviation on this ways:

\mu -3\sigma = 568     (1)

\mu +3\sigma = 1066   (2)

If we subtract conditions (2) and (1) we got:

1066-588 =\mu +3\sigma -\mu +3\sigma

478= 6\sigma

\sigma =\frac{478}{6}=79.667

3 0
3 years ago
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