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aev [14]
3 years ago
11

Help on second question ​

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

0.36

Step-by-step explanation:

you add the probability's together

quite simple really. -3-

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The area of a trapezoid field is 480 square m. The distance between two parallel sides is 15 m and one of the parallel sides is
Makovka662 [10]

Answer:

44m

Step-by-step explanation:

area  of a trapezoid = (a+b)* h/2

since the distance between two parallel sides is 15, that would be your height

plug everything in and you get:

480 = (20 + b) *15/2

b = 44

4 0
3 years ago
PLZ HELP ME
Likurg_2 [28]

Answer:

x ≈ 14.87

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )

x = \sqrt{221} ≈ 14.87 ( to the nearest hundredth )

8 0
2 years ago
What equal 27 on gif
natali 33 [55]
Then that would be 3 and 9.
8 0
2 years ago
What is the solution to this inequality?
Snezhnost [94]

Answer:

  • \boxed{\sf{D. \quad x < 3}}

Step-by-step explanation:

It is necessary to isolate the term of x from one side of an inequality to find its solution.

<h3>-4x-8>-20</h3>

<u>First, add by 8 from both sides.</u>

\sf{-4x-8+8 > -20+8}

<u>Solve.</u>

-20+8=-12

<u>Rewrite the problem down.</u>

\sf{-4x > -12}

<u>Multiply by -1 from both sides.</u>

(-4x)(-1)<(-12)(-1)

<u>Solve.</u>

<u>Multiply the numbers from left to right.</u>

(-12)(-1)=12

4x<12

<u>Divide by 4 from both sides.</u>

4x/4<12/4

<u>Solve.</u>


<u>Divide the numbers from left to right.</u>

12/4=3

<u>x<3</u>

  • <u>Therefore, the correct answer is D. x<3 (last option).</u>

I hope this helps you! Let me know if my answer is wrong or not.

5 0
2 years ago
Read 2 more answers
What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?
Darya [45]

Answer:

4 \sqrt{2} i

Step-by-step explanation:

We want to find the sum of

\sqrt{ - 2}  +  \sqrt{ - 18}

We can rewrite this as

\sqrt{ 2 \times  - 1}  +  \sqrt{ 18 \times  - 1}

This becomes;

\sqrt{2}  \times  \sqrt{ - 1}  +  \sqrt{18}  \times  \sqrt{ - 1}

Recall that;

i =  \sqrt{ - 1}

This implies that;

\sqrt{2} i + 3 \sqrt{2} i

Combine like terms:

4 \sqrt{2} i

3 0
3 years ago
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