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g100num [7]
3 years ago
11

arc GT = 18 degrees, arc TA =32 degrees, arc NA =112 degrees, arc IN = 74 degrees. find measure of angle GET

Mathematics
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

Step-by-step explanation:

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Elena L [17]
Y= ∛(-x) - 3
for x = -8 → y = ∛-(-8) - 3 ↔ y = 2-3 ↔y = -1
for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then  - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}
5 0
3 years ago
Could someone tell me the correct answer and how to do this. Plz help meeee I'm crying because I don't know how to do this stuff
WINSTONCH [101]
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8 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
lakkis [162]

Answer:

false i think? and true

Step-by-step explanation:


8 0
3 years ago
Need help with A and C <br><br>please :)
Dennis_Churaev [7]

First step: name the sides according to geometry standards, namely, the sides are named the same lowercase letter as the opposing angle. A revised diagram is shown.

Second step: we need to know the relationships of the trigonometric functions.

cosine(A)=cos(63) = adjacent / hypotenuse = AC/AB .................(1)

sine(A)=sin(63) = opposite / hypotenuse = CB/AB .......................(2)

We're given AB=7, so

using (1)

AC/AB=cos(63)

AC=ABcos(63)=7 cos(63) = 7*0.45399 = 3.17993 = 3.180 (to three dec. figures)

Using (2)

BC/AB=sin(63)

BC=ABsin(63) = 7 sin(63) = 7*0.89101 = 6.237 (to three dec. figures).


3 0
4 years ago
Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour, start at the same place and run along t
Vikentia [17]

Answer:

The Distance cover by both the Runners is same = 10 miles  

Step-by-step explanation:

According to question ,

The Speed of first runners (S 1) = 5 miles per hour

The speed of second runners (S 2)  = 4 miles per hour

Let The Time taken by First runner (T 1 ) = T hour

But the second runner  arrives half hour after the first runner ,

I.e The Time taken by Second runner (T 2) = ( T + \frac{1}{2} )

Now from Distance = Speed × Time

Since both the runners start from same place and run along the same trail

SO ,Both the Distance cover by both are same , D 1 = D 2

i.e Speed 1 × Time 1 = Speed 2 × Time 2

    5 mph × T            =  4 mph   ×  ( T + \frac{1}{2} )

    5 T =  4 T + ( 4 × \frac{1}{2} )

Or,  5 T - 4 T = 2

∴       T    =  2 hour  ,

Time take by first = T1 = T = 2 hour

Time take by second = T2 = T + \frac{1}{2} = (2  +  \frac{1}{2} )hour = \frac{5}{2}

Now the Distance cover = Speed × Time

              Distance   (D1)          = 5 mph  × 2 hour = 10 mile

And        Distance    (D2)         =  4 mph  × \frac{5}{2} = 10 miles

Hence, As The Distance cover by both the Runners is same = 10 miles  Answer

5 0
3 years ago
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