Answer:
(x-8) is the factor.
Step-by-step explanation:
The given trinomial is 
.
We need to find the factor of this trinomial.
The factors of is (x-2) and (x-8).
So, the factor of is (x-8). Hence, the correct option is (B).
Answer:
x = 1
Step-by-step explanation:
Given in the question the equation
y = -x² + 2x - 1
To find the x-intercept, substitute in 0 for y
0 = -x² + 2x - 1
To find value of x use quadratic equation
x = -b ± √b²-4ac / 2a
here a = -1
b = 2
c = -1
x1 = -2 + √2²-4(-1)(-1) / 2(-1)
= -2 + 0 / -2
= -2 / -2
= 1
x2 = -2 - √2²-4(-1)(-1) / 2(-1)
= -2 - 0 / -2
= -2 / -2
= 1
Answer:
2) 45
3) 25
4) 50%
5) 33.3%
6) 17.6
7) 500
8) 35%
9) 60
10) 87.5%
11) 2.64
12) 25%
13) 5.7
14) 85%
16) 75%
Step-by-step explanation:
2) 9 = 20% of x
9 * 5 = 45
3) 8% of x = 2
12.5 * 2 = 25
4) 39 = x(78)
39/78 = 1/2 = 50%
5) x(36) = 12
12/36 = 1/3 = 33.3...%
6) x = 0.8(22)
22/10 = 2.2
2.2* 8 = 16 + 1.6 = 17.6
7) 55 = 0.11(x)
55/11 = 5
5 * 100 = 500
8) 7/20 = 35/100 = 35%
9) 27 = 0.45(x)
27/45 = 3/5
3/5 * 100 = 300/5 = 60
10) . 49/56 = 7/8 = 0.875 = 87.5%
11) 6/100 = 0.06
0.06 * 44 = 2.64
12) 48/192 = 6/24 = 1/4 = 25%
13) 95/100 = 0.95
0.95 * 6 = 5.40 + 0.3 = 5.7
14) 68/80 = 34/40 = 17/20 = 85%
16) 108/144 = 9/12 = 0.75 = 75%
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-Chetan K
The answer is 31/3 or 10⅓
Using the normal distribution, it is found that the replacement time that separates the top 18% from the bottom 82% is of 11.23 years.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are, respectively, given by 
.
The desired value is the 82nd percentile, which is X when Z = 0.915, hence:
X - 9.4 = 0.915(2)
X = 11.23
The replacement time that separates the top 18% from the bottom 82% is of 11.23 years.
More can be learned about the normal distribution at brainly.com/question/24663213
