Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
Answer:
Subtraction property of equality
Step-by-step explanation:
c + 5 = 78
Subtract 5 from each side using the subtraction property of equality
c+5-5 = 78-5
x = 73
Answer: The factorization of 
The factors of are 28 and 1+2t+w.
Step-by-step explanation:
The given expression :
To factorize it, we need to find the common factor.
As 56 can be written as 2 x 28.
So, the above expression would become
Now, taking 28 as common from all the terms, we will get
Thus, the factorization of
And the factors of are 28 and 1+2t+w.
10m
The process of elimination
