The area of the circle = π r² = π (d/2)²
Where r is the radius of the circle
And d is the diameter of the circle
d = 2r OR r = d/2
given d = 10 in ∴ r = d/2 = 10/2 = 5 in
∴ The area of the circle = π r² = π * 5² = 25π ≈ 78.54 in²
The correct answer is the fourth option 78.54
==========================================
very important note:
There is a mistake in the dimension of the answers.
The dimension of the given diameter is inch , while the dimensions of the answers is square cm.
If it is required to find the area in square cm
∵ 1 inch = 2.54 cm
∴ r = d/2 = 10/2 = 5 in = 5 * 2.54 cm = 12.7 cm
∴ Area = π r² = π * (12.7)² = 161.29π ≈ 506.7 square cm
Answer:
2x^3
C
Step-by-step explanation:
Correct amswer is 4 whole pieces
Answer:
- 0 real zeros
- 2 complex zeros
Step-by-step explanation:
The "fundamental theorem of algebra" says a polynomial of degree n will have n zeros. If the polynomial has real coefficients, the complex zeros will appear in conjugate pairs.
The graph of this quadratic (degree = 2) does not cross the x-axis, so there are no real values of x that make y=0. That means the two zeros are both complex.
The given inequality is:
-5c + 2 ≤ 27
Subtracting 2 from both sides, we get:
-5c + 2 - 2 ≤ 27 - 2
-5x ≤ 25
Dividing by 5 on both sides we get:
- x ≤ 5
Multiplying by -1 we get:
x ≥ 5
Remember that multiplying or dividing by a negative number changes the direction of inequality symbol.
From the given options, the second graph correctly represents this solution.
