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Fantom [35]
3 years ago
12

If you can tell me the answer please do i need help besties​

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

51

Step-by-step explanation:

8.5/1

and

x/6

cross multiply

51=x

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in 2018 GRE scores were normally distributed with a mean of 303, and standard deviation of 13. Standford University Graduate sch
eduard

Answer:

The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 303, \sigma = 13

What is the minimum score needed to be considered for admission to Stanfords graduate school?

Top 2.5%.

So X when Z has a pvalue of 1-0.025 = 0.975. So X when Z = 1.96

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 303}{13}

X - 303 = 13*1.96

X = 328.48

The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.

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