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Fantom [35]
3 years ago
12

If you can tell me the answer please do i need help besties​

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

51

Step-by-step explanation:

8.5/1

and

x/6

cross multiply

51=x

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A contractor is calculating the number of decorative stones for a new rectangular patio. The bids always include a count for the
babunello [35]

Answer:

The number of edge stones needed has a constant rate of change, but the number of stones for the center does not.

Step-by-step explanation:

The complete question is shown in the picture attached below.

Two functions E(x) and C(x) are given in the table along with some of the function values. We have to identify if any of these functions show constant rate of change or not.

By constant rate of change we mean that the slope is constant or in other words, a linear relationship is shown by the function. For a Linear function, the  first differences of the function values are same.

By first differences we mean the difference between two consecutive output values. We can see that difference between consecutive input values is constant i.e. 1. If the difference between consecutive output values of any of the functions is same, then that function will be a Linear Function and, therefore, the rate of change for that function will be constant.

Lets analyze E(x) first. The output values are:

34, 52, 70 and 88

The difference between consecutive output values is:

18, 18 and 18

Since, this difference is constant, we can conclude that E(x) is a Linear function with a constant rate of change.

Now lets analyze C(x). The output values are:

62, 133, 260 and 435

The difference between consecutive output values is:

71, 127 and 175

Since, the differences are not constant, C(x) is not a Linear Function and , therefore, the rate of change of C(x) is not constant.

Conclusion:

The number of edge stones which is represented by E(x) has a constant rate of change, but the number of stones for center which is represented by C(x) does not have constant rate of change. This makes the first option our correct answer.

3 0
3 years ago
A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable
Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0
3 years ago
A factory makes candy bars and ships them in cases
il63 [147K]

Answer:

b, 24 bars per box

Step-by-step explanation:

you just tale 144÷6

8 0
3 years ago
what equation is used to represent "three minus the difference of a number and one equals one-half of the difference of three ti
sesenic [268]
(n-1)-3=1/2(3n-4)
hope it hrlps
8 0
4 years ago
Joel’s veterinarian tells him that he can give his dog 11 5/8 mg of Benadryl for relief of his dogs allergies. Joel’s dog weighs
Sav [38]

Step-by-step explanation:

Given that,

The dosage of Benadryl for Dog is 11\dfrac{5}{8}\ mg

Weight of Joel's Dog is 15\dfrac{1}{2}\ \text{pounds}

(a)  Benadryl dosage per pound for Joel’s dog is calculated as :

\dfrac{11\dfrac{5}{8}}{15\dfrac{1}{2}}=\dfrac{\dfrac{11\times 8+5}{8}}{\dfrac{15\times 2+1}{2}}\\\\=\dfrac{\dfrac{93}{8}}{\dfrac{31}{2}}\\\\=\dfrac{93}{8}\times \dfrac{2}{31}\\\\=0.75\ \text{dosage per pound}

(b) If the weight of the Dog is 12 pounds, it means

\dfrac{11\dfrac{5}{8}}{12}\ \text{dosage per pounds}\\\\=\dfrac{\dfrac{93}{8}}{12}\\\\=\dfrac{93}{8}\times \dfrac{1}{12}\\\\=0.968\ \text{dosage per pounds}

Therefore, this is the required solution.

3 0
3 years ago
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