Option B is right perpendicular bisectors of the sides of the triangle
<h3>What circumcircle?</h3>
If we draw a circle through all the vertices of a triangle then the circle obtained is the circumcircle of the given triangle. We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent. These three concur at a point called the circumcentre of the triangle.
When we draw a perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistant from A and B.
When we take the point of intersection of the perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short, this is equidistant from all 3 vertices and hence is the centre of the circumcircle of triangle ABC
Therefore Option B is right perpendicular bisectors of the sides of the triangle.
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A proportional relationship is used to illustrate linear equations.
The constant of proportionality is 3
From the table, we have the following points:
(x,y) = (2,6) (3,9)
The constant of proportionality is calculated using:

So, we have:

Subtract

Divide

Hence, the constant of proportionality is 3
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The 4th term of the sequence can be determined as,

Thus, option (b) is correct.
Anything times 0 is zero.
What number plus zero is equal to 7? 7.
Two numbers that add to 7 and multiply to 0 are 0 and 7.
0 x 7 = 0
0 + 7 = 7
<span>8x^2-8x-13 is the correct answer </span>