12! / 4!
= 1×2×3×4×5×6×7×8×9×10×11×12 / 1×2×3×4
= 5×6×7×8×9×10×11×12 = 19958400
Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)
Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points,
D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)
Answer:
m > 4
Step-by-step explanation:
5m - 8 > 12
Add 8 to each side
5m - 8+8 > 12+8
5m > 20
Divide by 5
5m/5 > 20/5
m > 4
Answer:
y = 12
Step-by-step explanation:
Looking at the large triangle
tan 30 = opposite / adjacent
tan 30 = 4 sqrt(3)/ y
Multiply each side by y
y tan 30 = 4 sqrt (3)
We know tan 30 = sqrt(3)/3
y * sqrt(3)/3 = 4 sqrt(3)
Multiply each side by 3/ sqrt(3) to isolate y
y * sqrt(3)/3 * 3/ sqrt(3) = 4 sqrt(3) * 3 /sqrt(3)
y = 12
Answer:
(4b-9) (4b+9)
Step-by-step explanation:
16b^2 – 81
This is the difference of squares
(a^2 -c^2) = (a-c) (a+c)
a^2 = 16b^2 so a= 4b
c^2 = 81 so c = 9
(16b^2 – 81) = (4b-9) (4b+9)
