Step-by-step explanation:
it can be written as. -4<_(3x+7)<_4
= -11 <_(3x) <_ (-3)
= (-11/3) <_ X <_ (-1)
Answer:
Using ∣x∣>a⇒x<−a or x>a, we get
∣3x−7∣>4⇒3x−7<−4 or 3x−7>4
⇒3x<3 or 3x>11⇒x<1 or x>
3
11
⇒x∈(−∞,1)∪(
,∞).
-20
first question: 2.62 or 2 31/50
second question: i dont know
