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denpristay [2]
3 years ago
12

6x^+4(x^-1) simply this question

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0
1. when you see 4(x² - 1), then you have to multiply 4 with everything in the bracket. keep in mind that you always have to be cautious of the sign whether it is a positive or a negative.

positive ×/÷ positive = positive
negative ×/÷ negative = positive
positive ×/÷ negative = negative
negative ×/÷ positive = negative

^ you have to remember this.

2. only like terms (same alphabet) can plus or minus each other.

3. simplify by taking out the common factor and placing it outside the bracket. though, keep in mind that you also have to divide the terms inside the bracket by the common factor.

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Solve the problem
Maru [420]

Answer:

C. 3363

Step-by-step explanation:

I calculated logically

7 0
3 years ago
2x+5>7 problem solving
Anna71 [15]

Answer:

x > 1

Step-by-step explanation:

2x+5>7

move constant to right

2x>5-7

subtract 7 and 5

2x>2

divide both sides

x > 1

7 0
3 years ago
Please help I was supposed to do this yesterday <br><br> If x=-4 and y= 9/2
tekilochka [14]

Answer:

1/6(3x^{2}+4y)

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The movie theater charges $4 for children, $6 for adults, and $5 for seniors. A group of 14 people decide to go to the movies. T
MaRussiya [10]

Answer:

Adults=8

Childrens=2

Seniors=2

Step-by-step explanation:

Children $4

Adults $6

Seniors $5

There are an equal number of seniors and children.

The entire group spent a total of $66.

If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.

If we add the charges of childrens and seniors is equal to $9.

Assuming that the group has 2 childrens and 2 seniors the add is equal to:

(2*5)+(2*4)= 18

Now we substract the result from the total amount:

66-18=48

48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.  

         

4 0
3 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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