2 years ago

The temperature went from -12°F to 18°F. How much did the temperature change?

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

4 0

Answer:

12+18=30

Step-by-step explanation:

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X + y = 4 3x + 4y= 14

Vaselesa [24]

Y = 4 - x
3x + 4(4-x) = 14
3x + 16 -4x = 14
-x = -2
x = 2
y = 2

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2 years ago

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A linear pair of angles have measures of 3m - 6 and 3m + 18. What is the value of m?

timama [110]

Answer:

the value of m = 28°

Step-by-step explanation:

the sum of adjacent angles which form linear pair is 180°

so,

=》3m - 6° + 3m + 18° = 180°

=》6m + 12° = 180°

=》6m = 180° - 12°

=》m = 168° ÷ 6

=》m = 28°

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3 years ago

What is the slope of this line

Elenna [48]

Answer:

Step-by-step explanation:

rise/run = slope

As it goes to the left or adds by one, it goes up by 4

4/1

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3 years ago

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Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb

Umnica [9.8K]

Answer:

It would roll in this direction.

$\nu = (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})$

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.

Since

$z = ax^2 + by^2$

For this case, the gradient of your function would be

$\nabla z = (2ax , 2by)$

And -1 times the gradient of your function would be

$-\nabla z = (-2ax , -2by)\\$

Then, at

$(1,1,a+b),\\x = 1 \\y = 1$

So it would go towards

$v = (-2a,-2b)$

The magnitud of that vector is

$|v| = 2\sqrt{a^2+b^2}$

and to conclude it would roll in this direction.

$\nu = (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})$

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2 years ago

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pochemuha

Put an open circle pointing to the left on -1

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3 years ago

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