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Simora [160]
3 years ago
14

How to solve 8 to the power of five thirds

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
4 0

8^\frac{5}{3}=8^{1\frac{2}{3}}=8^{1+\frac{2}{3}}=8\cdot8^\frac{2}{3}=8\sqrt[3]{8^2}=8\sqrt[3]{64}=8\cdot4=32\\\\Used:\\\\a^n\cdot a^m=a^{n+m}\\\\a^\frac{m}{n}=\sqrt[n]{a^m}\\---------------------------------\\Other\ method\\\\8=2^3\\\\8^\frac{5}{3}=(2^3)^\frac{5}{3}=2^{3\cdot\frac{5}{3}}=2^5=32\\\\Used:\\\\(a^n)^m=a^{n\cdot m}

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Is it possible for an object to have more than one input value, but only one output value
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Answer:

We conclude that it is possible for an object to have more than one input value, but only one output value.

Step-by-step explanation:

Yes, it is possible for an object to have more than one input value, but only one output value.

For example, considering the table having 'name' as the 'input' and the output as 'age'.

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Mr A                                       13

Mr B                                       14

Mr C                                       13

Mr D                                       15

Here, Each input has only input. But, multiple relatives can have the same age.

Here, Mr A and Mr C have the same 13 years age. This table represents a function.

Therefore, we conclude that it is possible for an object to have more than one input value, but only one output value.

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