Find the range for the function k(n) = 2n2 when D = {–2, 1, 3}. R = {2, 8, 18} R = {2, 18, 36} R = {4, 12, 27} R = {4, 12, 16}
lianna [129]
K(n) = 2n^2.....where domain (n) = -2
k(-2) = 2(-2^2) = 2(4) = 8
k(n) = 2n^2.....where n = 1
k(1) = 2(1^2) = 2(1) = 2
k(n) = 2n^2...where n = 3
k(3) = 2(3^2) = 2(9) = 18
so ur range k(n) = { 2,8,18}
Answer: $48.93
Step-by-step explanation: 789.18 x 0.062
12) The mistake that Liz made was instead of shading in 5% of the diagram, she shaded in 5 blocks, which is incorrect.
13) You would have to shade in only one block, because 5% of 20 (blocks) is 1.
Step-by-step explanation:
f(10)=10
f(-2)=-2
f(a)=a
f(a+b)=a+b
g(10)=5×10-12=3
g(-2)=5×(-2)-12=-10-12=-22
g(a)=5×a-12=5a-12
g(a+b)=5×(a+b)-12=5a+5b-12
h(10)=(10)^2 +4(10)-7=100+40-7=133
h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11
h(a)=a^2 +4a -7
h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7