To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
The graph of 
is given by,
Here given the function is 
when 
, then it passes through the origin (0,0).
When 
Since we know that, 
, then the function has maximum height at 
.
Again when 
, again the function is 0.
So clearly the function is the Oscillating function.
Using graphing calculator we get the graph of function 
,
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Answer c can you explain more
