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3 years ago

What do the differences between the equation of a

Mathematics

1 answer:

EastWind [94]3 years ago

8 0

Answer:

it tells u what color

Step-by-step explanation:

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Find the common ratio for the following geometric sequence. 0.75,1.5,3,6,...

Rasek [7]

Answer:

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...\ ,\ a_n\ \text{is a geometric series, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=r=constant$

$\text{We have}\ 0.75,\ 1.5,\ 3,\ 6,\ ...\\\\\text{The common ratio}\ r:\\\\\dfrac{1.5}{0.75}=2\\\\\dfrac{3}{1.5}=2\\\\\dfrac{6}{3}=2\\\\\boxed{r=2}$

4 0

3 years ago

A juggler perform in a telant contest. He is given 10 marks by each of the 4 judges. What’s his total score?

Mars2501 [29]

Answer:

Step-by-step explanation:

The answer is 40. There are 4 judges, and each gave him a 10. This can be shown by an equation.

1. 4 * 10 = total score

2. 40 = total score.

Hope this helps! (Please consider giving brainliest)

6 0

4 years ago

Read 2 more answers

Find the measure of angle Y

Oksana_A [137]

If all angles are equal it must be an equilateral triangle which means the measure of Y is 60°

6 0

3 years ago

What is the solution of -83=b/4

Gre4nikov [31]

I believe it is -332.
(-83= -332 ÷ 4)

6 0

3 years ago

The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4

Mrac [35]

Answer:

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

$Mean = x1 = \frac{20+24+40+63+76+89}{6}$

$x1 = \frac{312}{6}$

$x1 = 52$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

$20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37$

The deviations will be added then. $Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24$

So the mean absolute deviation for city 1 is 24 ..

For city 2:

$Mean = x2 = \frac{41+50+58+62+72+83}{6}$

$x2 = \frac{366}{6}$

$x2 = 61$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

$41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22$

The deviations will be added then. $Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33$

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

3 0

3 years ago

Read 2 more answers