Can somebody help me out with this question?
1 answer:
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The given polynomial is f(x) = x² - 2x - 6
Rewrite the function by completing the square.
f(x) = [x² - 2x] - 6
= [(x-1)² - 1] - 6
= (x-1)² - 7
In vertex form,
f(x) = (x-1)² - 7
The vertex is located at (1, -7).
Because the leading coefficient is +1, the curve opens upward.
Answer: f(x) = (x - 1)² - 7
Rewrite the function by completing the square.
f(x) = [x² - 2x] - 6
= [(x-1)² - 1] - 6
= (x-1)² - 7
In vertex form,
f(x) = (x-1)² - 7
The vertex is located at (1, -7).
Because the leading coefficient is +1, the curve opens upward.
Answer: f(x) = (x - 1)² - 7