All categories

2 years ago

2. A recipe calls for 2 1/3 cups of flour and 1/8 cup of baking soda "you are

Mathematics

1 answer:

Inga [223]2 years ago

5 0

Answer:18.7 or 56/3 cup of flour

Step-by-step explanation:

The solution is in the attached file

You might be interested in

If ƒ(x) = 5x − 2 and g(x) = 1 − 2x, find (ƒg)(x).

drek231 [11]

Answer:

Step-by-step explanation:

(fg)(x) = f(x)*g(x) = (5x-2)(1-2x) = 5x-10x^2-2+4x = a

4 0

2 years ago

What must be true about the average rate of change between any two points on the graph of an increasing function?

frez [133]

Are there options to choose from?

4 0

2 years ago

Joey is 5 years less than three times the age of his son. Joey is 43 years old.

Vikki [24]

Answer:

amogus

Step-by-step explanation:

6 0

2 years ago

What is equivalent to 13 - √-18? 4 13 - 9i 13 + 9i 22

beks73 [17]

√-1=i

13-√-18=
13-√(-1)(18)=
13-(√-1)(√18)=
13-(i)(3√2)=
13-3i√2

8 0

3 years ago

A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From

lutik1710 [3]

Answer:

a) $z = 1.645$

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ , which means that the answer of question a is z = 1.645.

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

$M = 12, \sigma = 124.88$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$12 = 1.645*\frac{124.88}{\sqrt{n}}$

$12\sqrt{n} = 205.43$

$\sqrt{n} = \frac{205.43}{12}$

$\sqrt{n} = 17.12$

$\sqrt{n}^{2} = (17.12)^{2}$

$n = 293$

The should sample at least 293 small claims.

8 0

2 years ago