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natima [27]
3 years ago
10

How many solutions are there to an inequality?

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer: 3

Step-by-step explanation: There can be none, one, or infinite solutions. Therefore there can be up to three possible solutions to an inequality.

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The perimeter of a rectangular swimming pool is 446 centimeters. The width of the pool is 7 centimeters less than the length of
VLD [36.1K]

Answer:

length = 115 cm

width = 108 cm

Step-by-step explanation:

The perimeter of a rectangular swimming pool is 446 centimeters

LEt L be the length of the pool

The width of the pool is 7 centimeters less than the length of the pool.

width = length - 7

W= L-7

Given perimeter = 446

Perimeter of rectangle = 2(length)+2(width)

446 = 2(L) + 2(W)                    we know W = L-7

446 = 2(L) + 2(L-7)    

446 = 2L + 2L - 14

Add 14 on both sides

460 = 4L

divide by 4 on both sides

L= 115

Length L= 115

Width W = L - 7 = 115 - 7= 108

5 0
3 years ago
Read 2 more answers
How many ways can we award a 1st, 2nd and 3rd place prize among eight contestants?
trasher [3.6K]

Answer:

Total number of ways are 336.

Step-by-step explanation:

It is required to find the number of ways in which we can award a 1st, 2nd and 3rd place prize among eight contestants. It means we need to find the number of permutations. We need to find ^8P_3.

Here, r = 3

So,

^nP_r=\dfrac{n!}{(n-r)!}\\\\^8P_3=\dfrac{8!}{(8-3)!}\\\\^8P_3=\dfrac{8!}{5!}\\\\^8P_3=\dfrac{8\times 7\times 6\times 5!}{5!}\\\\^8P_3=336

So, there are 336 ways.

6 0
3 years ago
Express 2 as a percentage (no links please)​
lys-0071 [83]
2 is equivalent to 200%

Multiply both numerator and denominator by 100. We do this to find an equivalent fraction having 100 as the denominator.
2 × 100/100

= (2 × 100) × 1/100= 200/100

percentage in notation is : 200%
7 0
3 years ago
Consider the expression below. Assume the variable m represents an integer. 6m(3m + 21) Enter an expression in the box that uses
Monica [59]

Answer:

(a)\ 6m(3m + 21) = 9(2m^2 + 14m)

(b) Yes, it is divisible by 9

Step-by-step explanation:

Given

6m(3m + 21)

Solving (a): Complete the blanks

6m(3m + 21) = 9 [\ ]

Expand the bracket

6m(3[m + 7]) = 9 [\ ]

6m*3(m + 7) = 9 [\ ]

Express 6m as 2m * 3

2m*3*3(m + 7) = 9 [\ ]

2m*9(m + 7) = 9 [\ ]

Rewrite as:

9 * 2m(m + 7) = 9 [\ ]

Multiply the bracket by 2m

9 * (2m^2 + 14m) = 9 [\ ]

Divide both sides by 9

2m^2 + 14m = [\ ]

<em>Hence, the bracket will be filled with: </em>2m^2 + 14m<em></em>

<em>So:</em>

6m(3m + 21) = 9(2m^2 + 14m)

Solving (b): Is 6m(3m + 21) divisible by 9?

In (a), we have:

6m(3m + 21) = 9(2m^2 + 14m)

The leading factor "9" implies that the expression is divisible by 9

4 0
3 years ago
Find each sum or difference. Show your work. <br><br> (x^3+2)+(-3x^3-5)<br><br> Plz help!
Sindrei [870]
Because  before parentheses is plus , we can simply remove parentheses
x³+2-3x³-5= (x³-3x³)+(2-5)=-2x³-3
3 0
4 years ago
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