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2 years ago

What is the correct notation for a function that has any given input value equal to its output value?

Mathematics

2 answers:

Ket [755]2 years ago

7 0

Answer:

0ption B is correct

ie:f(x) = x

Tatiana [17]2 years ago

4 0

Answer:

option B

Step-by-step explanation:

f(X) = x

is the answer

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ASAP

Stels [109]

Given :

Number of bags with raspberry scones and blueberry scones should be equal
The greatest number of bags need to be made where each of them has equal numbers of each scone.

Number of raspberry scones with Bryson = 51

Number of blueberry scones with Bryson = 34

To find the greatest number of bags Bryson can fill with equal number of raspberry and blueberry cones each, we need to find the GCF of the number of blueberry scones and raspberry scones.

Factors of 34 = 1, 2, 17, 34

Factors of 51 = 1, 3, 17, 51

Greatest common factor (GCF) of 34 and 51 = 17

Therefore, the greatest number of bags Bryson can fill with equal number of blueberry scones and raspberry scones = 17 bags

7 0

2 years ago

Algebra 2

denis23 [38]

Answer:

Complex numbers are the one having two parts:

Real part
Imaginary part

Each of the part is simplified to (a+ib) format.

I hope it will help you.

Step-by-step explanation:

All parts are solved below:

Part 1:

=(-8i) + (41)+(-3 - 7i)

opening brackets

=-8i+41-3-7i

Adding like terms, real to real and imaginary to imaginary

= 38-15i

Part 2:

= (7 + 5i) - (7 - i)

Negative sign before bracket will change the signs to opposite

=7+5i - 7+ i

Adding like terms, real to real and imaginary to imaginary

=0 + 6i

Part 3:

=(8 – 4i) - (5 – 4i)

Negative sign before bracket will change the signs to opposite

= 8-4i-5+4i

Adding like terms, real to real and imaginary to imaginary

=3+0i

Part 4:

=(-8 - 4i) - (8 + i)

Negative signs before bracket will change the signs to opposite

=-8-4i-8-i

Adding like terms, real to real and imaginary to imaginary

=-16-5i

Part 5:

=(-3 - i) + (7 + 2i)

=-3-i+7+2i

Adding like terms, real to real and imaginary to imaginary

=4+1i

Part 6:

=-2 +6-(-4 + 2i)

Negative sign before bracket will change the signs to opposite

=-2+6+4-2i

Adding like terms, real to real and imaginary to imaginary

=8-2i

Part 7:

=(3 - 8i)(-4 + 4i)

Multiplying both bracket we get:

=-12+12i+32i+32i^2

By putting i^2 = (-1)

=12 +44i + 32 (-1)

Adding like terms, real to real and imaginary to imaginary

= -20+44i

Part 8:

=(5 – 3i)(-7 - 2i)

Multiplying both bracket we get:

=-35-10i+21i+6i^2

=-31+11i + 6 (-1) (By putting i^2 = (-1))

Adding like terms, real to real and imaginary to imaginary

=-37+11i

Part 9:

=8 + 8i

Part 10:

=(7 - 5i)(-4 + 3i)

Multiplying both bracket we get:

=-28+21i+20i-15i^2 (By putting i^2 = (-1))

=-28+41i- 15(-1)

Adding like terms, real to real and imaginary to imaginary

=-13+41i

Part 11:

=7 + 4i

Part 12:

=(8 - 7i)(3 - 3i)

Multiplying both bracket we get:

=24-24i-21i+21i^2

=24-45i+21(-1) (By putting i^2 = (-1))

Adding like terms, real to real and imaginary to imaginary

=3-45i

3 0

3 years ago

What is the probability of rolling a number greater than or equal to 8 with the sum of two dice given that at least one of the d

Basile [38]

One in 6 because dice goes up to 6

5 0

3 years ago

Read 2 more answers

Desmond deposits $50 into a savings account every month at an annual interest rate of

joja [24]

Given:

Desmond deposits $ 50 monthly.

Yearly he deposits = $50×12 = $ 600

Rate of interest compounded monthly = 4.7%

To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.

Formula

$A = P(1+\frac{r}{(n)(100)} )^{nt}$

where,

A be the final amount

P be the principal

r be the rate of interest

t be the time and

n be the number of times the interest is compounded.

Now,

Taking,

P = 600, r = 4.7, n = 12, t = 10 we get,

$A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}$

or, $A = 600(1.0039)^{120}$

or, $A = 959.1$

Now,

At starting he has $ 600

At the end of 10 years he will be having $ 959.1

So,

The amount of change in his account = $ (959.1-600) = $ 359.1

Therefore the rate of change = $(\frac{359.1}{600} )(100) %$

= 59.85%

Hence,

a) His account will contain $ 959.1 after 10 years.

b) The rate of change in his account is 59.85% after 10 years.

7 0

2 years ago

I dont know how to do this pls help

Alecsey [184]

Answer:

1) 225

2) 2304

Step-by-step explanation:

Use geometric mean of legs

$x = \sqrt{(16+9)^2 * 9^2} = \sqrt{25^2 * 9^2} = 25 * 9 = 225$

Use geometric mean of altitude

$x = \sqrt{(100-36)^2 * 36^2} = \sqrt{64^2 * 36^2} = 64 * 36 = 2304$

5 0

3 years ago