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AnnZ [28]
3 years ago
15

Simplify each of the following.

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0
<h2>a.)</h2><h2>=  \frac{8192}{12 {x}^{3} {y}^{3}  }</h2><h2><em>b.</em><em>)</em></h2><h2><em>=  \frac{ {x}^{4} - 2 {x}^{3} y +  {x}^{2}   {y}^{2} }{3 {y}^{3} }</em></h2>

<em>hope </em><em>it</em><em> helps</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

<em>follow</em><em> me</em><em> and</em><em> mark</em><em> me</em><em> as</em><em> brainlist</em><em> plss</em>

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Matias stacked his cubes to make this rectangular prism. rectangular prism with grid lines How many cubes did Matias use?
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Counting each visible cube, and multiplying it by 2, he used 112. If you counted them, there would be 56 cubes. You'd multiply by 2 for the non-visible ones.
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Step-by-step explanation:

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I’m not sure how to solve this.. does anyone have the answer
WITCHER [35]

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3 years ago
Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

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Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of GT and EF

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Finally, we can use the Pythagorean Theorem to find the length of AG:

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8 0
2 years ago
9. Eric guessed that Troop A was going to have 23 members in 2011 when they actually had 20. How much was Eric off by in his est
julia-pushkina [17]

Answer:The answer is D

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Please make brainliest

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