Answer:
(b) 1.7 in
Step-by-step explanation:
The area of a regular polygon in terms of perimeter and apothem is given by the formula ...
A = 1/2Pa
For a hexagon, the perimeter is 6 times the side length, so this becomes ...
A = 1/2(6s)a = 3sa . . . . . for side length 's' and apothem 'a'
__
Solving for the apothem, we find ...
a = A/(3s)
For the given values of area and side length the apothem is ...
a = 10.4/(3·2) = 1.733... ≈ 1.7 . . . inches
The apothem, rounded to tenths, is 1.7 inches.
Y = -2/3x + 7.....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. All tht means is take the original slope, flip it, and change the sign. So we take -2/3....flip it making it -3/2.....change the sign making it 3/2. So ur perpendicular line will have a slope of 3/2.
y = mx + b
slope(m) = 3/2
(-5,6)....x = -5 and y = 6
now sub and find b, the y int
6 = 3/2(-5) + b
6 = -15/2 + b
6 + 15/2 = b
12/2 + 15/2 = b
27/2 = b
so ur perpendicular equation is : y = 3/2x + 27/2 <==
Answer:
hi im from another country see ya ... your country is amazing
Step-by-step explanation:
Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.
Multiply both top and bottom by that number.
Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>
Step-by-step explanation:
Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.
From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by
=
.
So, the population in the year t can be given by 
Population in the year 2000 =
=
Population in year 2000 = 3,762,979
Let us assume population doubles by year
.



≈
∴ By 2033, the population doubles.