Answer:
IQR = 6
Step-by-step explanation:
Given:
The given set of data is:
40 41 42 43 44 45 46 47 48 49 50
Number of terms, 
Therefore, the median is given as 
term which is the sixth term. Median = 45
(40 41 42 43 44) <u>45</u> (46 47 48 49 50 )
Now, we find the median of the lower half (
) and upper half (
)of the data that are before and after the median.
The lower half of the data has the values 40 41 <u>42</u> 43 44.
Number of terms are 5. So, median is the third term which is, 
The upper half of the data has the values 46 47 <u>48</u> 49 50.
Number of terms are 5. So, median is the third term which is, 
Now, IQR is given as the difference of upper half median and lower half median.
2x-6 (2) is your equation. follow these steps, and you have to distribute 6 into 2 like this: 2x-12. you get negative 12 because -6 x 2 =-12. now you divide -12 by 2 which is -6. So -6=x
Answer:
B. -6p-78
Step-by-step explanation:
-5(3p +3) +9(-7 +p) . . . . . given
-15p -15 -63 +9p . . . . . . . use the distributive property to eliminate parens
-6p -78 . . . . . . . . . . . . . . . collect terms
Answer:
6-4x
Step-by-step explanation:
Answer:
(B) π/12 + π/6 k
Step-by-step explanation:
Points of inflection are where f"(x) = 0 and changes signs.
f(x) = cos²(3x)
f(x) = (cos(3x))²
f'(x) = 2 (cos(3x))¹ × -sin(3x) × 3
f'(x) = -6 sin(3x) cos(3x)
Using double angle formula:
f'(x) = -3 sin(6x)
f"(x) = -3 cos(6x) × 6
f"(x) = -18 cos(6x)
0 = -18 cos(6x)
0 = cos(6x)
6x = π/2 + 2πk or 6x = 3π/2 + 2πk
We can simplify this to:
6x = π/2 + πk
x = π/12 + π/6 k
