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Vesnalui [34]
3 years ago
8

!!!!!!PLEASSEE HELP VIEW PICTURE!!!!

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0
The answer is 12 because it’s a circle and that dot in the middle is the radius. so the radius is 6 which mean the diameter is 2x that making it 12
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What the equivalent expression. 5 (3m +2p) - 4m​
Ad libitum [116K]
Hi the answer is 11m+10p
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If you decided to build a ramp using the 1:16 slope - ratio requirement , what would be the length of the diagonal portion of th
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3 years ago
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Which of the following points are on the line given by the equation y = 5x?
ivanzaharov [21]

Answer:

C and E

Step-by-step explanation:

To answer this question, we plug in the X values of the coordinates into the equation to see if they'll give us the corresponding Y value.

(X, Y)

Example:

Y = 5X

6 != 5 * 3

We do this for every coordinate point. If the problem doesn't make sense, it doesn't fall on the line. Let's test every one of these.

B. (0, 1)

1 != 5 * 0

C. (3, 15)

15 = 5 * 3

D. (4, 2)

2 != 5 * 4

E. (-1, -5)

-5 = 5 * -1

F. (-1, 5)

5 != 5 * -1

* For those who don't know, the !=  is how to say "not equal to" in computer science.

3 0
3 years ago
Derive the equation of the parabola with a focus at (−5, −5) and a directrix of y = 7
WARRIOR [948]

Answer: The equation of the parabola is (x+5)^2=-24(y-1).

Explanation:

It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.

The standard form of the parabola is,

(x-h)^2=4p(y-k)

Where y=k-p is directrix and (h,k+p) is the focus.

Since focus is given,

(h,k+p)=(-5,-5)

On comparing,

h=-5

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The directrix is y=7.

k+p=7       .... (2)

Add equation (1) and (2),

2k=2

k=1

Put this value in (1).

p=-6

Put p= -6, h= -5 and k=1 in the standard form of the parabola.

(x+5)^2=4(-6)(y-1)

(x+5)^2=-24(y-1)

Therefore, the equation of parabola is (x+5)^2=-24(y-1).

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3 years ago
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Find the condition that one root of the quadratic equation may be 1 more than the other.
Eddi Din [679]
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
4 0
3 years ago
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