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ExtremeBDS [4]
3 years ago
9

Which of these is NOT an advantage of the impact of computer careers.

Computers and Technology
1 answer:
Illusion [34]3 years ago
5 0

An increase in the number of stress and health concerns that result from working in a computer environment.  
Let's look at the available options and see what is, or is not an advantage.  
Web designers have created websites that allow individuals to shop, promote business, bank, and communicate via social media sites.
 * This means that people don't actually have to travel in order to do their business and meet new people. Sounds like an advantage to me, so this is a bad choice.  
An increase in the number of stress and health concerns that result from working in a computer environment. 
* Hmm. People getting sick. Doesn't sound like anything I'd like. So this isn't an advantage and is the correct answer.  
Medical diagnoses can be made earlier 
* Faster diagnoses of diseases. Sounds like an advantage to me. So this is a bad choice.  
Businesses can save costs on travel by meeting online using teleconference options 
* Saving money and time. Sounds like an advantage. So this is a bad choice.
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In computer science what are the methods used to protect the information stored by a piece of software called?
Nezavi [6.7K]

Answer:

cryptography

Explanation:

cryptography

In computer science, cryptography refers to secure information and communication techniques derived from mathematical concepts and a set of rule-based calculations called algorithms, to transform messages in ways that are hard to decipher

3 0
2 years ago
CHALLENGE ACTIVITY |
fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0
3 years ago
Draw a flowchart to compute sum A=10 &amp; B=20​
Tamiku [17]

Answer: i add the asnwer

Explanation:

7 0
3 years ago
Explain and Define the four types of maintenance in IT?
crimeas [40]

Answer:

 The four types of maintenance in IT are given as:

Preventive maintenance: It is the important part to facilitates the management system and it should be designed carefully o prevent them from failure. the main aim of preventive maintenance is to successfully establish the design to improve the system performance.

Corrective maintenance:  It basically refers to the changes made to repair the defects in the implementation and designing of the system. It is usually performed after the failure occur in the equipment. It also increased overall productivity of the system.

Perfective maintenance: It basically improve the performance of the system, efficiency and maintainability. This type of maintenance are initiated by the IT department.

Adaptive maintenance: It involves the implementation changes in the system to increase its functionality. It basically improve its efficiency and increase its capability. It is less urgent than corrective maintenance.

7 0
3 years ago
Can someone compress this ipv6 address? 558c:0000:0000:d367:7c8e:1216:0000:66be
zaharov [31]

558c::d367:7c8e:1216:0:66be

7 0
3 years ago
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