Answer:
The program is as follows:
<em>5 INPUT A,B</em>
<em>6 PROD = A * B</em>
<em>7 PRINT PROD</em>
<em>8 TOTAL = A + B</em>
<em>9 PRINT TOTAL</em>
<em>10 DIFF = A - B</em>
<em>11 PRINT DIFF</em>
<em>12 END</em>
Explanation:
This gets input for the two numbers
<em>5 INPUT A,B</em>
This calculates the product
<em>6 PROD = A * B</em>
This prints the calculated product
<em>7 PRINT PROD</em>
This calculates the sum
<em>8 TOTAL = A + B</em>
This prints the calculated sum
<em>9 PRINT TOTAL</em>
This calculates the difference
<em>10 DIFF = A - B</em>
This prints the calculated difference
<em>11 PRINT DIFF</em>
This ends the program
<em>12 END</em>
guess its d drivers , since u said wen it gets outdated
I think it's having a trusted adult with you to drive
Answer: Hello your question is poorly written attached below is the well written question
answer:
a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons
time efficiency = θ( n )
b) A(n-1) - A(0)
time efficiency = θ( 1 )
Explanation:
a) An unsorted array
To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons
Algorithm's time efficiency = θ( n )
b) A sorted array
To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)
time efficiency = θ( 1 )
Answer:
(i) When transmitting a draft manuscript for a book, the lossless compression technique is most suitable because after decompression, the data is rebuilt and restored in its form as it was from where it originated
(ii) When transmitting a video recording which you have made of the school play, a lossy compression technique is most suitable because the large size of video files require the increased data carrying capacity which is provided by the lossy transmission technique. The quality of the video can be reduced without affecting the message intended to be delivered
Explanation: