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Alina [70]
3 years ago
12

What does it mean for a temperature to be below zero? Provide an example.

Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer:

ice to water to fire to coal to burnt fiber to gas

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For every 5 female teachers, there are 2 male teachers
gtnhenbr [62]

Answer:

so if there are 10 female teachers then there are 4 male teachers

Step-by-step explanation:

please mark brainliest

4 0
3 years ago
Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer
defon

Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.

So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.

For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).

Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)\neq 0.

So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1.

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

7 0
3 years ago
Consider U = {x|x is a real number}. A = {x|x ∈ U and x + 2 > 10} B = {x|x ∈ U and 2x > 10} Which statements are true? 5 ∉
-Dominant- [34]

x+2 > 10 solves to x > 8 after we subtract 2 from both sides

So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.


Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.


----------------


Summarizing everything, we can say...

5 is not in set A. True

5 is in set B. False

6 is in set A. False

6 is not in set B. False

8 is not in set A. True

8 is in set B. True

9 is in set A. True

9 is not in set B. False


5 0
3 years ago
Read 2 more answers
Estimate 32% of 19.
Kipish [7]

Answer: 13

Step-by-step explanation: calculator

5 0
3 years ago
Read 2 more answers
Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the
beks73 [17]
In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: m= \frac{P( \frac{r}{12}) }{1-(1+ \frac{r}{12})^{-12t}  }
where
m is the monthly payment
P is the amount
r is the interest rate in decimal form 
t is the number years

First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
\frac{4}{100} =0.04
We also know from our question that P=224500 and t=30, so lets replace those values into our formula to find the monthly payment:
m= \frac{224500( \frac{0.04}{12}) }{1-(1+ \frac{0.04}{12})^{-(12)(30)}  }
m=1071.80

We can conclude that the monthly payment during the initial period is $1071.58<span />
7 0
3 years ago
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