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EastWind [94]
3 years ago
11

Simplify (9s/2t)* (2s/3)

Mathematics
2 answers:
ozzi3 years ago
8 0

Answer:

3s^2/t

Step-by-step explanation:

(9s/2t)* (2s/3)

Multiply the numerators

9s*2s = 18s^2

Multiply the denominators

2t*3 = 6t

Put the numerator over the denominator

18s^2/6t

Divide the top and bottom by 6

3s^2/t

ehidna [41]3 years ago
3 0

Answer:

You'd get 18s^2/6t by simply multiplying. To simplify just decide each sides by 6 and you'd get 3s^2/t

Step-by-step explanation:

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y=x-1

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Consider these dimensions for a cylindrical aquarium.
vagabundo [1.1K]

The amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

<h3>What is a Cylindrical figure ?</h3>

A cylinder is a three dimensional figure with two identical circular faces at each end , and a curved surface.

It does not have an edges or vertices.

It is given in the question that

A cylinder with height 14 feet and radius 25 feet.

The volume of a cylinder.

V = π252(14)

The water than can be filled is equal to the volume of the cylinder

V = 11088 cu.ft

There  the amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

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brainly.com/question/10369419

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6 0
1 year ago
5. Vena finds lost balls and sells them. After selling 13, she had 22 balls left. How many golf balls did Vena have
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Step-by-step explanation:

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5 0
3 years ago
Solve (x + 5)^(3/2)= (x - 1)^3
IRINA_888 [86]

Answer:

  x = 4

Step-by-step explanation:

For an equation of this sort, my first step is to rewrite it so the solutions are the x-intercepts of the graph:

  (x +5)^(3/2) -(x +1)^3 = 0

The graph is attached. The one real solution is x=4.

__

The solution method for something like this is necessarily ad hoc. Here, it appears that progress can be made by raising both sides of the equation to the 2/3 power:

  ((x +5)^(3/2))^(2/3) = ((x -1)^3)^(2/3)

  x +5 = (x -1)^2

Now, you have an ordinary quadratic that can be solved using any of the usual methods.

  x^2 -2x +1 = x +5 . . . . swap sides, expand the square

  x^2 -3x -4 = 0 . . . . . . put in standard form

  (x -4)(x +1) = 0 . . . . . . factor

The solutions to this are ...

  x = 4, x = -1 . . . . . . . values of x that make the factors zero

__

To see if either of these solutions is extraneous, we can check them:

  (4 +5)^(3/2) = (4 -1)^3 . . . . . substitute 4 for x

  9^(3/2) = 3^3 . . . . . . . . . true

  (-1 +5)^(3/2) = (-1 -1)^3 . . . . . substitute -1 for x

  4^(3/2) = (-2)^3

  8 = -8 . . . . . . . . . . . false; x = -1 is extraneous

The solution is x = 4.

_____

<em>Additional comment</em>

You can eliminate the x=-1 "solution" by considering the domains of the left- and right-side expressions. The 3/2 power is equivalent to the square root of the cube. That will generally only be defined for non-negative values (x ≥ -5). The cube on the right will only be positive for x > 1, so the practical domain of this equation is x ≥ 1.

5 0
2 years ago
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