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velikii [3]
3 years ago
13

Find the measure of the missing angles.​

Mathematics
2 answers:
olganol [36]3 years ago
8 0

Step-by-step explanation:

  1. x°+38°+90°=180°

x°+128°=180°

x°=180°-128°

x°=52

2. y-90°=x

y-90°=52°

y=52°+90°

y=142°

butalik [34]3 years ago
5 0

Answer:

0507   y 2

Step-by-step explanation:

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Ju-yi just got back from A 10 mile bicycle ride and she had ridden three miles per hour faster. The ride would have taken her 30
Gnom [1K]

Answer:

6.39\ miles/hr

Step-by-step explanation:

Let\ her\ speed=x\ mile/hr\\\\Let\ time\ taken=t\ hr\\\\distance=speed\times time\\\\10=x\times t\ .........................(1)

When speed is 3 mi/hr faster.

Her\ speed=x+3\ mile/hr\\\\Time\ taken=t-\frac{1}{2}\ hr\ \ \ as\ it\ takes 30\ minutes\ fewer\ and\ 30\ min=\frac{1}{2}\ hr\\\\distance=speed\times time\\\\10=(x+3)\times (t-\frac{1}{2})\\\\10=xt+3t-\frac{x}{2}-\frac{3}{2}\......................eq(2)\\\\eq(2)-eq(1)\\\\10-10=xt+3t-\frac{x}{2}-\frac{3}{2}-xt\\\\3t=\frac{x}{2}+\frac{3}{2}\\\\t=\frac{x+3}{6}\\\\from\ equation\ 1\ t=\frac{10}{x}\\\\\frac{10}{x}=\frac{x+3}{6}\\\\60=x^2+3x\ \ \ \ \ \ \ \ \ cross\ multiplication\\\\x^2+3x-60=0

Solution\ of\ ax^2+bx+c=0\ is\ given\ by\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\Here\ a=1,b=3\ and c=-60\\\\x=\frac{-3\pm\sqrt{3^2-4\times 1\times (-60)}}{2}\\\\x=\frac{-3\pm\sqrt{9+240}}{2}\\\\Only\ positive\ value\ will\  be\ taken\\\\x=\frac{-3+\sqrt{9+240}}{2}=6.39\ miles/hr

7 0
3 years ago
Jack owns a small restaurant called Best Burgers. For one week, he collected sales data on the type of side order served with ea
kicyunya [14]

Answer:

The answer is C) 54 pounds

Step-by-step explanation:

because im batman

6 0
4 years ago
Help me ill give yall 97 points good luck
lilavasa [31]

Answer:

ok im not sure what ur asking but the square root of 625 is 25 the square root of 196 is 14 the square root of 961 is 31 and the square root of 100 is 10 hope this helped if not im sry

Step-by-step explanation:

5 0
3 years ago
3^-6 x (3^4 / 3^0)^2
inna [77]

Answer:

9 x

Step-by-step explanation:

Simplify the following:

((3^4/3^0)^2 x)/(3^6)

Hint: | Compute 3^6 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^6 = (3^3)^2 = (3×3^2)^2:

((3^4/3^0)^2 x)/((3×3^2)^2)

Hint: | Evaluate 3^2.

3^2 = 9:

((3^4/3^0)^2 x)/((3×9)^2)

Hint: | Multiply 3 and 9 together.

3×9 = 27:

((3^4/3^0)^2 x)/(27^2)

Hint: | Evaluate 27^2.

| 2 | 7

× | 2 | 7

1 | 8 | 9

5 | 4 | 0

7 | 2 | 9:

((3^4/3^0)^2 x)/729

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 3^4/3^0.

Combine powers. 3^4/3^0 = 3^(4 + 0):

((3^4)^2 x)/729

Hint: | For all positive integer exponents (a^n)^m = a^(n m). Apply this to (3^4)^2.

Multiply exponents. (3^4)^2 = 3^(4×2):

(3^(4×2) x)/729

Hint: | Multiply 4 and 2 together.

4×2 = 8:

(3^8 x)/729

Hint: | Compute 3^8 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^8 = (3^4)^2 = ((3^2)^2)^2:

(((3^2)^2)^2 x)/729

Hint: | Evaluate 3^2.

3^2 = 9:

((9^2)^2 x)/729

Hint: | Evaluate 9^2.

9^2 = 81:

(81^2 x)/729

Hint: | Evaluate 81^2.

| | 8 | 1

× | | 8 | 1

| | 8 | 1

6 | 4 | 8 | 0

6 | 5 | 6 | 1:

(6561 x)/729

Hint: | In (x×6561)/729, divide 6561 in the numerator by 729 in the denominator.

6561/729 = (729×9)/729 = 9:

Answer:  9 x

3 0
3 years ago
Read 2 more answers
What are the reasons for these statements
Tems11 [23]
Think of two lines BE and AD that intersect at C and makes triangles BAC and EDC since angles BCA and ECD are equal by opposite angle thereom. and given BC=EC, CA=CD there the triangles are equal and side BA=ED
5 0
3 years ago
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