distance = Sqrt((x2-x1)^2 +(y2-y1)^2)
15-3 =12
16-7=9
12^2 = 144
9^2 = 81
144+81 = 225
square root of 225 = 15
the distance is 15
Answer:
The present was 300 feet above ground 5 seconds after being thrown.
6.47 seconds passed before the present hit the ground.
Step-by-step explanation:
We have the following quadratic function

Which determines the height of the present.
Determine when the present was 300 feet above the ground.
This is when
. So



This is
and
. There are no negative time instants. So the present was 300 feet above ground 5 seconds after being thrown.
Determine how many seconds passed before the present hit the ground.
This is t when 



6.47 seconds passed before the present hit the ground.
Well you have to multipy 4 x 11 and then add 4 x 10
Answer:
i can explai it to u if u wan to get the answer
Step-by-step explanation:
Divide the polygon into 5 triangles by using each side as a base and joining the vertices of the polygon to a common point (for example, the centre). If the polygon is regular the angle at the vertex of each triangle is 360/5=72 degrees, so you have 5 isosceles triangles of equal area. Find the area of one and multiply by 5 to get the total area.multiply 5 times the lenght of oneside
The question is asking us to multiply and simplify the equation square root of 6 times the square root of 2. To do this, we must first transform the whole question into numbers. Doing so, we get:

Now, we straight up multiply 6 and 2:

The answer to your problem is

. Hope this helps and have a great day!