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MA_775_DIABLO [31]
3 years ago
10

Evaluate. −38 − 39 − 14 A) −91 B) −15 C) 47 D) 63

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

It is (A) -91

Hope this helps. Have a good day!!

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1 point) during a winter season at one ski resort, there are two roads from area a to area b and two roads from area b to area
miss Akunina [59]
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)

Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
5 0
3 years ago
Assume that the Poisson distribution applies and that the mean number of aircraft accidents is 9 per month. Find​ P(0), the prob
Ugo [173]

Answer: 0.0001

It is unlikely to have a month with no aircraft​ accidents .

Step-by-step explanation:

Given :  Mean number of aircraft accidents = 9 per month

The Poisson distribution formula :-

\dfrac{e^{-\lambda}\lambda^x}{x!}, where \lambda is the mean of the distribution.

If X = the number of aircraft accidents per month, then the probability that in a​ month, there will be no aircraft accidents will be :-

\dfrac{e^{-9}(9)^0}{0!}=0.000123409804087\approx0.0001

Hence, the probability that in a​ month, there will be no aircraft accidents = 0.0001

Since this is less than 0.5 , therefor it is unlikely to have a month with no aircraft​ accidents .

5 0
3 years ago
Starting at sea level, a submarine descended at a constant rate to a depth of − 4/5 mile relative to sea level in 3 minutes.
Jobisdone [24]
If it were 4 then it would be 1 1/3 for one minute
5 0
3 years ago
Read 2 more answers
P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Mila [183]

Answer:

The polynomial is:

p(x) = -x^3 - 2x^2 + 5x + 6

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that x_1 = -3, x_2 = -1, x_3 = 2. Thus

p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)

p(x) = a(x - (-3))*(x - (-1))*(x-2)

p(x) = a(x+3)(x+1)(x-2)

p(x) = a(x^2+4x+3)(x-2)

p(x) = a(x^3+2x^2-5x-6)

Passes through the point (1,12).

This means that when x = 1, p(x) = 12. We use this to find a.

12 = a(1 + 2 - 5 - 6)

-12a = 12

a = -\frac{12}{12}

a = -1

Thus

p(x) = -(x^3+2x^2-5x-6)

p(x) = -x^3 - 2x^2 + 5x + 6

6 0
3 years ago
5. Which numbers below are composite?<br> 13<br> 15<br> 17<br> 27<br> Help
yan [13]

Answer:

15 and 27 are composite

Step-by-step explanation:

prime numbers only factor into 1(x) and x(1)

13 = 1(13), 13(1)

15 = 1(15), 3(5), 5(3), 15(1)

17 = 1(17), 17(1)

27 = 1(27), 3(9), 9(3), 27(1)

hope this helps

7 0
3 years ago
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