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2 years ago

A linear function has an x-intercept of 12 and a slope of 3/8. How does this

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

5 0

Answer:

O It has the same slope and a different y-intercept.

Step-by-step explanation:

y = mx + b

m = 3/8

b = 12

y = (3/8)x + 12

---

Data in the table: slope is the rise (y) over the run (x) between two points (assuming the data represent a linear line).

Change in x and y between two points. I'll choose (-2/3,-3/4) and (1/3,-3/8).

Change in y: (-3/8 - (-3/4)) = (-3/8 - (-6/8)) = 3/8

Change in x: (1/3 - (-2/3)) = (1/3+2/3) = 3/3 = 1

Slope = (Change in y)/(Change in x) = (3/8)/1 = 3/8

The slope of the equation is the same as the data in the table.

Now let's determine if the y-intercept is also the same (12). The equation for the data table is y = (2/3)x + b, and we want to find b. Enter any of the data points for x and y and then solve for b. I'll use (-2/3, -3/4)

y = (3/8)x + b

Use (-2/3, -3/4)

-3/4 =- (3/8)(-2/3) + b

-3/4 = (-6/24) + b

b = -(3/4) + (6/24)

b = -(9/12) + (3/12)

b = -(6/12)

b = -(1/2)

The equation of the line formed by the data table is y = (3/8)x -(1/2)

Therefore, It has the same slope and a different y-intercept.

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Forensic specialists can estimate the height of a deceased person from the lengths of the person's bones. These lengths are subs

Lera25 [3.4K]

Answer:

$130.2845\leq h\leq 137.7245$

Step-by-step explanation:

Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation

$|h - (2.47f + 54.10)| \leq 3.72$

If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:

$|h - (2.47(32.25) + 54.10)| \leq 3.72\\|h - (79.9045 + 54.10)| \leq 3.72\\|h - (134.0045)| \leq 3.72\\$

If the modulus function is positive then:

$h - 134.0045 \leq 3.72\\h \leq 3.71+134.0045\\h\leq 137.7245$

If the modulus function is negative then:

$-(h - 134.0045) \leq 3.72\\-h+134.0045 \leq 3.72\\-h\leq 3.72-134.0045\\-h\leq -130.2845\\$

multiply through by -1

$-(-h)\geq -(-130.2845)\\h\geq 130.2845\\130.2845\leq h$

combining the resulting inequalities, the estimate of the possible range of heights will be $130.2845\leq h\leq 137.7245$

8 0

3 years ago

The question is below

Ad libitum [116K]

Answer:

£59.25

Step-by-step explanation:

Hello!

To solve this problem, we must:

Solve for the length of the fence (aka height)
Find the area of the lawn (trapezoid)
Find the number of cans needed
Find the price of all the cans

Area of a trapezoid, and why the formula works:

A trapezoid is a quadrilateral with one set of parallel sides known as bases. The other two sides are known as the legs.

To find the area of a trapezoid, we use the formula:

$\frac{B_1 + B_2}{2}* h$

This works because if we used the formula, we would be duplicating the trapezoid to form a rectangle with a side length of B1 + B2, and a height of h. Since the trapezoid is half of that, we divide by 2.

Solve for height:

The height is unknown but can be found using the Pythagorean Theorem.

The difference between the bases is the length of the bottom leg of the right triangle, and 17 is the hypotenuse.

Difference = 20 - 12 = 8

Hypotenuse = 17

8² + fence² = 17²
64 + fence² = 289
225 = fence²
fence = 15

The height is 15

Solve for area:

Now we can solve for the area.

$A = \frac{B_1 + B_2}{2} * h$
$A = \frac{12 + 20}{2} * 15$
$A = \frac{32}{2} * 15$
$A = 16 * 15 = 240$

The area is 240

Cans:

The area of the lawn is 240 square meters. Each can cover 100 square meters.

240 ÷ 100 = 2.4

Since we can't use part of a can, we round up to three whole cans.

The price of 3 cans :

3 * 19.75
59.25

£59.25

The Pythagorean Theorem:

The Pythagorean theorem is a very common geometry formula used to find the length of the hypotenuse in a right triangle, given the lengths of the two other bases.

The formula is : $a^2 + b^2 = c^2$

a is a leg
b is a leg
c is the hypotenuse

Images attached for your reference

7 0

2 years ago

Mathematics

Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

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1 year ago

X - 2 > 4 <br> What is the answer?

Rina8888 [55]

Answer:

$x - 2 > 4 \\ then \\ x = 4 + 2 \\ therefore \\ x = 6$

Step-by-step explanation:

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3 years ago

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2 years ago