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egoroff_w [7]
3 years ago
5

Is the decimal for 4 over 3 a repeating decimal ? expain

Mathematics
2 answers:
Alenkasestr [34]3 years ago
5 0

Yes, the decimal form of \frac{4}{3}is indeed a repeating decimal. The expression is equivalent to 1 \frac{1}{3}, which is also 1.3333333 or "1.3 bar", signifying that the 3 will repeat infinitely.

fgiga [73]3 years ago
5 0

Either using a calculator or long division, we can show that 4/3 = 1.333333...

Because this string of 3's goes on infinitely, 4/3 is indeed a repeating decimal.

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A recipe for brownies calls for 1/8 cup of sugar and the recipe makes 12 brownies what fraction of a cup is in each brownie? THA
denis23 [38]

Answer: \frac{1}{96}

Step-by-step explanation:

(\frac{1}{8})/12

Divide the fraction \frac{1}{8} by 12. This is because we need to split the sugar between 12 brownies, and to split something means to divide it. Use the switch, flip and multiply method.

I inserted an image on how to use this method.

Anyway, to use this method, we need 2 fractions, so instead of 12, we have to use \frac{12}{1}.

\frac{1}{8}/\frac{12}{1}

= \frac{1}{8} × \frac{1}{12}      Multiply the denominators and numerators

= \frac{1}{96}

7 0
3 years ago
4. Solve the inequality. 9+8 l 4a - 5 l >113​
OLga [1]

Answer:

i need this for a challenge

Step-by-step explanation:

3 0
3 years ago
What are some easy ways to find the value of<br> (2017^4−2016^4)/(2017^2+2016^2) without calculator
scoray [572]

Answer:

4033

Step-by-step explanation:

An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:

a^2 = 2017^4

a = 2017^2

b^2 = 2016^4

b = 2016^2

Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:

<h3>\frac{(2017^2+2016^2)(2017^2 - 2016^2)}{2017^2+2016^2}</h3>

We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by \frac{2017^2+2016^2}{2017^2+2016^2} which is just one, and will simplify the fraction to just:

2017^2 - 2016^2

This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:

(2017 + 2016)(2017 - 2016)

And, without using a calculator, this is easy to simplify:

(4033)(1)

4033

8 0
2 years ago
Help pleaseeee <br><br> 3.3 - 5.7n – 3n +8= ??
nasty-shy [4]

Answer:

11.3 - 8.7n

Step-by-step explanation:

Its almost basically combining like terms

You subtract - 5.7n - 3n to get -8.7n, then you add 3.3 + 8 to get 11.3 and you finally put it an equation 11.3 - 8.7n

5 0
3 years ago
Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.​
Dimas [21]

Answer:

The nonzero value of c will be:

  • c = 6

Step-by-step explanation:

Given the function

f\left(x\right)=\:x^2-4x-c

f\left(c\right)=\:c^2-4c-c

as

f(c) = c

so

c=\:c^2-4c-c

switching the sides

c^2-4c-c=c

subtract c from both sides

c^2-4c-c-c=c-c

c^2-6c=0

c\left(c-6\right)=0

Using the zero factor principle

\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

c=0\quad \mathrm{or}\quad \:c-6=0

so, the solutions to the quadratic equations are:

c=0,\:c=6

Therefore, a nonzero value of c will be:

  • c = 6
5 0
3 years ago
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