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madam [21]
3 years ago
7

Can someone help me?? 24x-18

Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer:

If you are factoring the answer should be 6(4x-3).

Step-by-step explanation:

Helen [10]3 years ago
8 0

Answer:

-432

Uh have a good day

:)

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Ivan

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3 years ago
Solve the problem. Find the surface area of a right regular hexagonal pyramid with sides 2 cm and slant height 5 cm. Round youra
BabaBlast [244]

Answer:

The surface area of the right regular hexagonal pyramid is 50.78 cm².

Step-by-step explanation:

Given:

A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.

Now, to find the surface area(SA) of the right regular hexagonal pyramid.

So, we find the area of the base(b) first:

Area of the base = \sqrt[3]{3}\times s^{2}

                            = \sqrt[3]{3}\times 2^{2}

On solving we get:

Area of the base(b) = 20.784

Then, we find the perimeter(p) :

Perimeter = s × 6

p=2\times 6=12

Now, putting the formula for getting the surface area:

Surface area = perimeter × height/2 + Area of the base.

SA=\frac{p\times h}{2}+b

SA=\frac{12\times 5}{2}+20.784

SA=30+20.784

SA=50.784

As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>

Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².

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A conical tank (with vertex down) is 12 feet across the top and 18 feet deep. If water is flowing into the tank at a rate of 18
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Step-by-step explanation:

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Step-by-step explanation:

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The answer fam is.......... "b.up"

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