Answer:
21+/-sqrt(253)=x
So one value for x is 21+sqrt(253)
and another is 21-sqrt(253)
Problem:
Given (21,7) and (x,1), find all x such that the distance between these two points is 17.
Step-by-step explanation:
Change in x is x-21
Change in y is 7-1=6
distance^2=(change in x)^2+(change in y)^2
17^2=(x-21)^2+(6)^2
289=(x-21)^2+36
Subtract 36 on both sides:
289-36=(x-21)^2
253=(x-21)^2
Take square root of both sides:
+/-sqrt(253)=x-21
Add 21 on both sides:
21+/-sqrt(253)=x
The rectangle is 7 x 4 so the area is 28 sq cm
The triangle has a base of 4 and a height of 3.
The formula is A = 1/2 * b*h
You have 2 triangles so:
2(1/2)*4*3= 12 sq cm
Add together:
28 + 12= 40 sq cm
The car was towed 44miles (162 - 30 = 132. 132 divided by 3 = 44)
