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Volgvan
3 years ago
10

PLEASE HELP DUE SOON 60 POINTS, EASY WORK!

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:-2, 4, -4

Step-by-step explanation:

Graph

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Identify the range of the function.<br> A) (-4,4)<br> B) [-4, 4]<br> C) (-4,4]<br> D) (-4,4)
Rasek [7]

Answer:

C) (-4, 4]

General Formulas and Concepts:

<u>Algebra I</u>

  • Range is the set of y-values that are outputted by function f(x)

Step-by-step explanation:

From the graph we see that our y-values span from -4 to 4. When y = -4, it is a open dot, meaning it is exclusive. When y = 4, it is a closed dot, meaning it is inclusive. Therefore, our range is:

(-4, 4] or -4 < y ≤ 4

7 0
3 years ago
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Write the ratio as a fraction in simplest form,with whole numbers in the numerator and denominator 42 to 6
nadya68 [22]
42/6 simplified equals 7/1 or just 7
4 0
3 years ago
The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width , what are the dimensions?
lianna [129]
Let the length be \ell and the width be w. Now, write the length in terms of the width. "The length is 15 cm. less than twice the width" in the form of an equation is

\ell = 2w - 15 cm.

Let's plug that into the equation for the perimeter now. The perimeter of a rectangle is 2 \ell + 2w, so the equation for the perimeter of this rectangle is

2 \ell + 2w = 102 cm.

Plugging in the length in terms of width and solving for the width, we get

2(2w - 15 cm.) + 2w = 102 cm.
6w - 30 cm. = 102 cm.
6w = 132 cm.
\bf w = 22 cm.

To find the length, we just have to plug in the width into the equation we wrote for the length in terms of the width:

\ell = 2w + 15 cm.
\ell = 2(22 cm.) - 15 cm.
\bf \ell = 29 cm.
7 0
3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
scZoUnD [109]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<em>A) If the length of a rectangle was tripled, but the  width did not change?</em>

<em>Perimeter</em>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

<u>Area</u>

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em>

<u>Perimeter</u>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

<u><em>Area</em></u>

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

4 0
3 years ago
Given that <br><img src="https://tex.z-dn.net/?f=2%20%7B%7D%5E%7Bx%7D%20%20%3D%200.125" id="TexFormula1" title="2 {}^{x} = 0.12
Luda [366]
Take the natural log of both sides

ln(2^x)=ln(.125)
Xln(2)=ln(.125)
X=ln(.125)/ln(2)
X=-3

ALTERNATIVE ROUTE:
You know that 0.125 is equal to 1/8
And 1/2^3 is also equal to 1/8
So since you need the reciprocal to match it the exponent is a negative
5 0
3 years ago
Read 2 more answers
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