This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
64 - 9 = 55 \sqrt{55} = 7.4161984871
7.4161984871/2 ≈3.7
Answer:
4 units to the right & 1 unit up.
Answer:
Step-by-step explanation:
f(x)=x+4(x^2+2x-3)=4x^2+9x-12
f'(x)=8x+9
f'(x)=0,gives x=-9/8
f(-5)=-5+4(-5-1)(-5+3)=-5+4*-6*-2=43
f(-9/8)=-9/8+4(-9/8-1)(-9/8+3)
=-9/8+4*-17/8*15/8
=-9/8-255/16
=-273/16=-17 1/16
f(5)=4*5^2+9*5-12=100+45-12=133
absolute maximum=133
absolute minimum=-17 1/16
