1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio039 [100]
2 years ago
9

Mr Ahmad bought 2 fans and 3 table lamps for $540. Each fan cost 3 times as much as a table lamp. (a) Find the cost of each tabl

e lamp. (b) Find the cost of each fan.​
Mathematics
1 answer:
sergey [27]2 years ago
4 0

Answer:

(a) $60

(b) $180

Step-by-step explanation:

Let the price of 1 table lamp be t.

Then the price of a fan is 3t.

2(3t) + 3t = 540

6t + 3t = 540

9t = 540

t = 60

A table lamp costs $60.

3($60) = $180

A fan costs $180.

You might be interested in
SOLVE EACH EQUATION CHECK FOR EXTRANEOUS SOLTUIONS.
Anna007 [38]

Answer:

(i)x=-8

(ii)y>18

(iii)x>10

Step-by-step explanation:

I think the ans above is correct.

I hope it will help u....

4 0
3 years ago
The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
HELP DUE LIKE RIGHT NOW​
Nimfa-mama [501]

Answer:

The correct answer is x = 17.

Step-by-step explanation:

If EF bisects DEG, this means that angles DEF and angles FEG are congruent, and they each make up half of angle DEG.

Therefore, we can set up the equation:

DEF + FEG = DEG

However, since we know that DEF and FEG represent the same value, we can change this equation into the following:

2(DEF) = DEG

Now, we can substitute in the expressions that we are given:

2(3x+1) = 5x + 19

To simplify, we should first use the distributive property on the left side of the equation.

6x + 2 = 5x + 19

Our next step is to subtract 5x from both sides of the equation.

x + 2 = 19

Finally, we can subtract 2 from both sides of the equation to get x by itself on the left side.

x = 17

Therefore, the value of x is 17.

Hope this helps!

7 0
4 years ago
150 is 55% of what number
balandron [24]
Simple, just divide the number by the percentage and you get the original number. You can check it by multiplying the original number of 272 by 55% or .55 to get 150.
150/.55 = 272
7 0
3 years ago
What is the value of x in this equation?
Naily [24]

Answer:

(B) 4

Hope this helps :)

8 0
3 years ago
Other questions:
  • 62 less than twice victors score
    10·2 answers
  • Two small pizzas with diameter 10 cost $15, while a large pizza with diameter of 16 cost $17 which pizza is less expensive per s
    12·1 answer
  • Are 4/5 and 1/2 equivalents?
    13·1 answer
  • Simplify 2(3x+7)-4(7+x)
    5·1 answer
  • Find the area of the circle if r = 5 meters. leave the answer in terms of π.
    6·2 answers
  • Use Pascal's triangle to find 6C3
    6·2 answers
  • Calculate the length of side AC:
    7·1 answer
  • What is the equation of the line that has a slope of 4 and passes through the points (9,4)
    10·2 answers
  • -3x-2+7x=10 please help
    7·2 answers
  • If the perimeter of an equilateral triangle is 30cm, find its area. ​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!