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Vinvika [58]
3 years ago
8

Need help with a and b parts

Mathematics
1 answer:
Masja [62]3 years ago
6 0

Answer:

a)  10/27 or 0.37037

b) -8/7

Step-by-step explanation:

a)  Enter x=-5 into both equations and divide h(-5)/g(-5).  That yields 10/27 or 0.37037037037 . . .

b) g(x) cannot be 0 (can't divide by 0.  That would occur if x = -8/7, so it (-8/7) is not in the domain.

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What is 2x + 4x + 4 = 4(x + 4) and step by step and Highlight / circle the error
mario62 [17]

Answer:

x = 6 and the +4x is wrong

Step-by-step explanation:

2x + 4x + 4 = 4(x + 4)

6x + 4 = 4x + 16

+4x +4x  <--( <u>This part is wrong</u> )

10x + 4 = 16

-4 -4

10x = 12

10 10

x = 1.2

Correct steps

2x + 4x + 4 = 4(x + 4)

6x + 4 = 4x + 16

-4x        -4x

2x + 4  = 16

      -4     -4

2x = 12

2       2

x = 6

6 0
3 years ago
I need help with this... please log(x+3)64=3
nikdorinn [45]

Answer:

you got this

Step-by-step explanation:

4 0
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Kamila [148]

Answer:

Which explains the information needed to calculate speed and velocity?

Both require the total distance, but velocity also requires time and displacement.

Both require time, but velocity requires displacement and speed requires distance.

Speed requires displacement, while velocity requires distance.

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Step-by-step explanation:

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3 years ago
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Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
A scuba diver is at an elevation of −38feet. The diver starts moving at a rate of −12 feet per minute. Identify an inequality th
solniwko [45]

Answer:

x = 13 1/2 or 13.5

Step-by-step explanation:

Flip Equation

-38 - 12x = -200

-12x -38 = -200

Add 38 to both sides

-12x -38 + 38 = -200 + 38

-12x = -162

Divide

-12x/-12 = -162/-12

x = 27/2

Simplify

27/2 = 13 1/2

x = 13 1/2

7 0
3 years ago
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