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Naddika [18.5K]
3 years ago
6

PLEASE LOOK AT PICURE!!! I WILL MARK BRAINIEST TO WHOEVER IS CORRECT!!!

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

\sqrt{113}

Step-by-step explanation:

(-9, -1), (-1, 6)

x1 = -9

x2 = -1

y1 = -1

y2 = 6

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

d = \sqrt{(-1 - (-9))^2 + (6 - (-1))^2}

d = \sqrt{8^2 + 7^2}

d = \sqrt{64 + 49}

d = \sqrt{113}

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
nataly862011 [7]

Answer:

$18.750

Step-by-step explanation:

8 0
4 years ago
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Find the length of the third side to the nearest tenth.
Aliun [14]

Answer:

5.3

Step-by-step explanation:

You use the Pythagoras theorem which is a^2+b^2=c^2.

Since you're solving for a side length that's not the hypotenuse you will manipulate the equation to c^2-a^2=b^2. From here you just plug in numbers.

8^2 - 6^2 = b^2

64 - 36 = b^2

b = sqrt(28)

b = 5.2915.... = 5.3

8 0
3 years ago
What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

  (a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
Grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height. how high
bezimeni [28]

Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.

So if D is the diameter and h is the height of the conical pile then we can write:


D=3h

We know that diameter = 2r, where r is the radius

2r=3h

r=\frac{3h}{2}

Volume of conical pile is given by formula

V=\frac{1}{3}\pi r^2h

Given that volume is 1110 cubic feet.

Now plug the values of Volume and r into equation of volume

1110=\frac{1}{3}\pi (\frac{3h}{2})^2h

1110=\frac{1}{3}\pi\cdot\frac{9h^2}{4}\cdot h

1110=\pi\cdot\frac{3h^3}{4}

1110\cdot\frac{4}{3\pi}=h^3

471.098631552=h^3

take cube root of both sides

7.78103342467=h

Hence height is approx 7.78 feet.

7 0
4 years ago
PLEASE HELP!!! WILL MARK AS BRAINLISTS!!!
Serjik [45]

The limit is x---->4-

The negative show that x approaches from the left

Now

As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.

Let's pick a Number

Say 3.99

Substitute this... You have

3.99/3.99-4

3.99/-0.01

If we choose x to be 3.999

we will have

3.999/-0.001

Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY

Why?

As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result

In our case... The denominator is negative... So it Will Approach a very Huge Negative Number

Hence

Answer.. X WILL APPROACH NEGATIVE INFINITY.

Vertical asymptotes are the zeroes of the denominator of a function

The denom. is x-4

Equate to zero to get the asymptote

x-4=0

x=4

Hence... There will be a vertical asymptote at x=4.

Have a great day!

7 0
3 years ago
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