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Elden [556K]
3 years ago
13

Find the length of EF

Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

9

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: 3x - 28 + 3x - 30 + x = 33

3. (Solving for x)

Step 1: Simplify both sides of the equation.

  • 3x - 28 + 3x - 30 + x = 33
  • (3x+3x+x) + (-28-30)=33
  • 7x - 58 = 33

Step 2: Add 58 to both sides.

  • 7x - 58 + 58 = 33 + 58
  • 7x = 91

Step 3: Divide both sides by 7.

  • \frac{7x}{7} = \frac{91}{7}
  • x = 13

4. Now that we know x is equal to 13, we can plug that value in for the expression 3x - 30.

  • 3(13)-30
  • 39 - 30
  • 9

Therefore, the length of EF is 9.

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98, 64, 75, 57, 86, 60, 91, 98, 79
astraxan [27]

Answer:

The median is 79

The median of the first quartile is 62

The median of the third quartile is 94.5

The inter quartile range is 32.5

Step-by-step explanation:

The median is the middle number of arranged number from smallest to greatest

The median of the first quartile is the middle number of the numbers before the median

The median of the third quartile is the middle number of the numbers after the median

The inter quartile range is the difference of the median of the 3rd quartile and the median of the 1st quartile

The numbers are 98, 64, 75, 57, 86, 60, 91, 98, 79

Let us arrange the numbers from small to big

57, 60, 64, 75, 79, 86, 91, 98, 98

They are 9 numbers

The middle one is the 5th number (4 before it and 4 after it)

The 5th number is 79

The median is 79

The numbers before the median are 57, 60, 64, 75

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 60 and the 3rd number is 64

The median of the first quartile = \frac{60+64}{2} = 62

The median of the first quartile is 62

The numbers before the median are 86, 91, 98, 98

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 91 and the 3rd number is 98

The median of the third quartile = \frac{91+98}{2} = 94.5

The median of the third quartile is 94.5

The inter quartile range = third median - first median

First median = 62

Third median = 94.5

Inter quartile range = 94.5 - 62 = 32.5

The inter quartile range is 32.5

7 0
3 years ago
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