Find the value of X in that isosceles triangle shown below
1 answer:
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Answer:
(-3, 1) quadrant II (2)
Step-by-step explanation:
An image of the coordinate plane is show. The quadrants start at the top right and move around in the counter-clockwise direction. The x-axis is horizontal (side to side) and y-axis is vertical (up and down). Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis. If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y) or in quadrant II.
General Idea:
When we are given a point P(x, y) centered at origin with a scale factor of k, then the dilated point will be given by P' (kx, ky)
Applying the concept:
In the diagram given, the coordinate of C is (6, 3). Triangle ABC is being dilated with the center of dilation at the origin. The image of C, point C' has coordinates of (7.2, 3.6).
If C (x, y) centered at origin with a scale factor of k, then the dilated point will be given by C' (kx, ky)
We know &
Substituting 6 for x in the equation , we get
.
Dividing 6 on both sides
Simplifying fractions on both sides
Point A from the diagram is (-3, 3)
x-coordinate of A' =
y-coordinate of A' =
Point A' is given by (-3.6, 3.6)
Conclusion:
<u>Scale factor of dilation is 1.2</u>
<u>The coordinates of point A' is (-3.6, 3.6)</u>