Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
ABC~WXY by AA
Step-by-step explanation:
In ΔABC
∠B = 90°
∠A = 27°
To Find ∠C
Angle sum property: The sum of all angles of triangle is 180°
∠A+∠B+∠C=180°
27°+90°+∠C=180°
∠C=180°-117°
∠C=63°
In ΔWXY
∠X = 90°
∠Y = 63°
We will use angle sum property
So, ∠W+∠Y+∠X=180°
90°+63°+∠W=180°
∠W=180°-(90°+63°)
∠W=27°
So, ∠A=∠W
∠B =∠X
∠C = ∠Y
So, ABC~WXY by Angle - Angle property.
Hence ABC~WXY by AA
Answer:
0 is an integer of the number
It’s going to be north in the east
Answer:
Basketball court is half mile away and the distance between pool and basketball court is 1 mile.
