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Vitek1552 [10]
2 years ago
13

the radius of a cylindrical construction pipe is 2.5 ft. if the pipe is 21 ft long, what is its volume? use the value 3.14 for p

i and round your anwser to the nearest whole number be sure to include the correct unit in your anwser
Mathematics
2 answers:
STatiana [176]2 years ago
8 0

Answer:


Step-by-step explanation:

Pi x r^2 x h

Pi x 2^2 x 23

= 289 ft^3

Hope this helps :-)

pishuonlain [190]2 years ago
7 0

Answer: The volume of the pipe is 412 cubic feet

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a cylinder = π x radius² x height (Length in this case)

Replacing with the values given:

V = 3.14 (2.5)² 21 = 3.4 (6.25) 21 = 412.12 = 412 cubic feet  (rounded)

In conclusion, the volume of the pipe is 412 cubic feet

Feel free to ask for more if needed or if you did not understand something.

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andreyandreev [35.5K]

Answer:

x=1.....................

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3 years ago
2+1.25f=10−2.75f solve for f
Inga [223]
Hey there!

2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.

1.25f + 2.75f = 4f

4f + 2 = 10
Subtract 2 from both sides.

4f = 8
Divide both sides by 4 to solve for f.

f = 2

I hope this helps!
6 0
3 years ago
Fatima is shading this model to show 0.08x3 . shade the correct amount of boxes that will show the product
Karo-lina-s [1.5K]
Shade 0.08 3 times

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7 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
Hey loves, plz help if you have time:)
aksik [14]

Answer:

ΔABX and ΔEDX

Step-by-step explanation:

Given: AX ≅ EX

          BX ≅ DX

SAS implies a congruent relation with respect to Side-Angle-Side between the two required triangle.

AX ≅ EX (given)

BX ≅ DX (given)

<BXA ≅ <DXE (vertical opposite angles)

Therefore,

ΔABX ≅ ΔEDX (Side-Angle-Side, SAS, congruence property)

3 0
3 years ago
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