Y= 2x-4
4x+Y=2
4x+2x-4=2
6x-4=2
+4=+4
6x=6
6/6X = 6/6 X=1
Y=2X-4
2(1)-4
Y=-2
Answer:
fourth option
Step-by-step explanation:
Given
3x < - 9 ( divide both sides by 3 )
x < - 3
solution set is { x | x < - 3 }
My suggestion is to look on google, there are plenty of answers and I think it will explain better than me.
Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answer:
The total number of students in a survey is 300.
Let the number of junior male(JM) be x and the number of senior males(SM) be y.
Let the number of junior female(JF) be p and the number of senior males(SF) be q.
It is given that there are 160 males, 80 junior females, 130 seniors.
Since number of males are 160. So the number of females are,
Since number of junior females is 80.
Since number of seniors are 130.
Since number of males is 160.
Therefore, the table and venn diagram is shown below.
