P(7,6), Q(1,6), R(4,2)
We have PQ parallel to the x axis. We'll call that the base,
b = 7 - 1 = 6
The altitude is then the y difference h = 6 - 2 = 4
The area is
Answer: 12 square units
In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:
(7,6), (1,6), (4,2)
(1,6), (4,2), (7,6)
The area is then half the absolute value of the sum of the cross products:
Answer:
<h2>181.33</h2>Step-by-step explanation:
Since the base of the pyramid PABCD is a rectangle, the shape in question is a rectangular based pyramid. Volume of a rectangular based pyramid is expressed as V = 1/3 * Base Area * Height of the pyramid.
Given a rectangle ABCD with AB = 8 and BC = 4, the area of the rectangle will be equivalent to the base area of the pyramid.
Base Area = Length * Breadth
Base Area = AB * BC
Base Area = 8*4 = 32
If , and PB = 17, then the height of the pyramid is PB = 17.
Volume of the pyramid = 1/3 * 32 * 17
Volume of the pyramid = 1/3 * 544
Volume of the rectangular based pyramid = 181.33
Answer:
or
Step-by-step explanation:
We know that the slope of the line is 1, so we can write it in terms of any two points belonging to the line, as per the difinition of slope:
We can use instead of any general point (x,y) on the line, and for
the point we are interested in: (11,4)
That way the slope can be written as:
Next we can solve for y if this format is the one your instructor prefers: