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goldenfox [79]
3 years ago
10

-3x+2y=-4 Graphed Very confused on this question

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Step-by-step explanation:

Given equation:  -3x + 2y = -4

Add 3x to both sides of the equation:

-3x + 2y + 3x = -4 + 3x

2y = 3x - 4

Divide both sides by 2 to solve for y:

\frac{2y}{2} = \frac{3x - 4}{2}

y = \frac{3}{2}x - 2  (This is the linear equation in slope-intercept form).

To graph, we could determine the y-intercept of the equation. The y-intercept is the value of y when x = 0.  

Plug in x = 0 into the equation:

y = \frac{3}{2}x - 2

y = \frac{3}{2}(0) - 2

y = - 2  

Therefore, the y-intercept is (0, -2).

Now, we can plot the points on the graph using the slope,  m = \frac{3}{2} = \frac{rise}{run}. Start by plotting the y-intercept onto the graph, then you can plot the next graph by going 3 units up and 2 units to the right. Keep repeating the steps until you form a line. Please see the plotted points in the attached image.  

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vlabodo [156]

You are correct for part A, good job! :D

As for part B, I <em>believe</em> the answers are function, nonlinear, and discrete.

Please let me know if I was wrong at any time. I hope this helps!!

4 0
3 years ago
Leo's lawn care charges 72$ for the first hour of mowing, plus 45 for each additional hour. which equation represents this situa
larisa86 [58]

Answer:

e &a

Step-by-step explanation:

45 is the slope (m)

72 is the y-intercept (0,72)

8 0
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Step-by-step explanation:

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Explain how to determine (calculate) the perfect squares
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Answer:A perfect square is a number which is generated by multiplying two equal integers by each other. For example, number 9 is a perfect square because it can be expressed as a product two equal integers being: 9 = 3 x 3.

Step-by-step explanation:

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3 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
4 years ago
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