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aivan3 [116]
3 years ago
12

2. A student measured the mass and volume of three different-sized samples of sand. He then calculated the

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

9514 1404 393

Answer:

  we expect the results to have less spread

Step-by-step explanation:

The spread between the maximum and minimum is almost 1/3 of the average of those values (0.8 vs 2.6). We expect repeated measurements of the same physical value to be well within 5% of their mean if they are done carefully.

The investigation has errors because the spread is too great.

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(3,2) is the solution

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8 0
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How to solve this? I'm new to it
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Which expression is equivelent to (-2)(a+6) <br> -2a+6 <br> 2a+12 <br> -2a-12 <br> -2a+12
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7 0
3 years ago
Please help!
erik [133]
For the answer to the question above, 
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3 

<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
5 0
3 years ago
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