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3 years ago

Solve each inequality

Mathematics

1 answer:

Yanka [14]3 years ago

7 0

17) -3 + x > 19
x > 19 +3
x > 22
18) -3 <_ 6x - 1
(Here, please note that <_ is lesser than or equal to and >_ is greater than or equal to)
6x >_ -2
x >_ -1/3

19, 20, 21) now onward Ima type just the answers -_-
x > -7/2
x < 12
x<_ 2

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How do I find the sum of this series?<br>Question D

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Sum of an infinite geometric sequence with the common ratio r, and the first term a1 is $\frac{a_1}{1-r}$

we notice
-2 times -1/4=1/2,
1/2 times -1/4=-1/8
so a1=-2
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$\frac{-2}{1+0.25}$ =
$\frac{-2}{1.25}$ =
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3 years ago

Describe a situation that fits each equation. Describe more than one situation for each equation, if possible.

lisabon 2012 [21]

Answer:

Step-by-step explanation:

4x − 1 = 19

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x=7

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2 years ago

Which of the following is the graph of the rational function? y=x^2+2x-8/x^2-9

rusak2 [61]

Notice that we can simplify both numerator and denominator of our rational function. In the numerator we have a quadratic expression of the form $ax^2+bx+c$ . To to simplify it, we are going to find tow numbers that add to 2 and multiply to -8; those numbers are 4 and -2.
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In the denominator we have a difference of squares:
$x^2-9=x^2-3^2=(x+3)(x-3)$

Now we can rewrite our function:
$y= \frac{x^2+2x-8}{x^2-9} = \frac{(x+4)(x-2)}{(x+3)(x-3)}$

From the simplified form of our rational function we can infer that its graph has two vertical asymptotes at $x=3$ and $x-3$

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3 years ago

Which out of these numbers has the same absolute value as one another and please help I don't really understand absolute value

Mariulka [41]

Answer:

Step-by-step explanation:Absolute value is a number's distance away from zero. For example, on a number line, -9 is 9 spaces away from zero. So, the absolut value is 9. Similarly, the number 9 is also 9 spaces from zero, so the absolute value would be 9. 9 and -9 both have an absolute value of 9. I hope this is helpful!

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3 years ago

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What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis

Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

Step-by-step explanation:

$\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}$

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

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3 years ago

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